2018 Neco Mathematics Objective and Theory Questions and Answers is available ,Mathematics 2018 Neco Exam Expo, all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
Neco maths portal
MATHS OBJ:
110: CDAAEABAEC
1120: ACDDCDCDACu
2130: CEADEDCABC
3140: CBEECCBDCC
4150: DDCBCDDBBA
5160: BCECCBBCEE
(1a)
Log10(20x  10)  log10(x+3) = log10^5
Log10(20x10/x+3)= log10^5
20x  10/x + 3 = 5
Cross multiplying
20x  10 = 5(x + 3)
5(4x  2) = 5(x + 3)
4x  2 = X + 3
4x  x = 3+2
3x = 5
X = 5/3 OR 1 whole no 2/3
(1b)
Let actual amount be #X
15% of #x = #600
15x/100 = 600
X = (100/15)*600
X = 100*40
X = 4,000
Actual amount = #4,000
(2a)
(X^2 Y^3 Z)^3/4/X^1 Y^4 Z^5
= (X^2)^3/4/X^1 * (Y^3)^3/4/Y^4 * Z^3/4/Z^5
= X^3/2/X^1 * Y^9/4/Y^4 * Z^3/4/Z^5
=X^3/2+1 * Y^9/44 * Z^3/45
=X^5/2 * Y^25/4 * Z^17/4
=X^10/4 * Y^25/4 * Z^17/4
=(X^10/Y^25 Z^17)^1/4
(2b)
√2/k + √2 = 1/k  √2
Multiply both sides by (k+√2)(k√2)
√2(k√2) = k+√2
√2k√2 = k+√2
√2kk = 2+√2
K(√2 1) = 2+√2
K = 2+√2/√21
K = (2+√2)/1√2
Rationalizing
K = (2+√2) * 1+√2/1√2
K = (2+√2)(1+√2)/1  2
K = (2+√2)(1+√2)
K = 2+2√2 + √2+2
K = 4+3√2
(4)
Draw the diagram
(i) Arc length = Tita/360*2πr
= 72/360*2*22/7*14
=1/5*44*2
=88/5
=17.6cm
(ii) Perimeter of Sector = arc length +2r
=17.6+2(14)
=17.6+28
=45.6cm
(iii) Area of sector = Tita/360*πr²
=72/360*22/7*14/1*14/1
=1/5*22*2*14
=616/5
=123.2cm2
(5a)
Mode = mass with highest frequency = 35kg
Median is the 18th mass
= 40kg.
(5b)
In a tabular form
Under Masses(x kg)
30,35,40,45,50,55
Under frequency(f)
5,9,7,6,4,4
Ef = 35
Under XA
10, 5, 0, 5, 10, 15
Under F(XA)
50, 45, 0, 30, 40, 60
Ef(X  A) = 35
Mean = A + (Ef(X  A)/Ef)
= 40 + 35/35
= 40 + 1
= 41kg
(
x=a+by(eqi)
when y=5 and x=19
19=a+5b(eqii)
when y=10 and x=34
34=a+10b(eqiii)
solving eqii and eqiii
a+10b=34
a+5b=19
=>5b=15
b=15/5=3
putting b=3 in eqii
19=a+5(3)
19=a+15
a=1915
a=4
(8i)
Putting a=4 and b=3 in eqi
x=4+3y
This is the relationship between xand y
(8ii)
When y=7
x=4+3(7)
x=4+21
x=25
11a)
x+y/2 =11
x+y= 11*2
x+y= 22 (1)
xy= 4 (11)
x+y = 22(1)

xy= 4(11)
____________
2y = 18
y= 18/2
y=9
Substitute y=9 in equ 1
x+9=22
x=229
x=13
x=13, y=9
x+y= 13+9= 22
Sum of the two number
(11b)
(6x + 3) dx
(6x + 3)dx
(6x +3)^6  (6x + 3)^1
(6 x + 3)^5
(7776x^5 + 243)
38,880x/6 + 243
6480 x^6 + 243x
9(720x^6 + 27x)
(11c)
y = x² + 5x  3 (x = 2)
y = 2² + 5(2)  3
y = 4 + 10  3
y = 14  3
y = 11
Gradient of the curve = 11
Monday 4th June 2018
OBJ � General Mathematics � 10:00am � 11:45am
Essay � General Mathematics � 12:00noon �2:30pm
Mathematics Neco exam will be deliver Night Before the exam day, we are not going to post answers here for free, Check our previous exam>>> 2018 Neco Geography Objective & Practical / Physical Questions and Answers  Geography Expo
Also Read>> Neco 2018 Whatsapp Exam Runs Package  Neco Exam Expo
Also Read>> 2018 Verified Neco Timetable
Note: please do not call our number, simply send message on whatsapp or using SMS
2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
Also Read>> 2018 Neco Biology Objective and Essay Questions and Answers  Biology Expo
2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
Last edited by Emmi on Mon Jun 04, 2018 11:58 am; edited 6 times in total
Neco maths portal
MATHS OBJ:
110: CDAAEABAEC
1120: ACDDCDCDACu
2130: CEADEDCABC
3140: CBEECCBDCC
4150: DDCBCDDBBA
5160: BCECCBBCEE
(1a)
Log10(20x  10)  log10(x+3) = log10^5
Log10(20x10/x+3)= log10^5
20x  10/x + 3 = 5
Cross multiplying
20x  10 = 5(x + 3)
5(4x  2) = 5(x + 3)
4x  2 = X + 3
4x  x = 3+2
3x = 5
X = 5/3 OR 1 whole no 2/3
(1b)
Let actual amount be #X
15% of #x = #600
15x/100 = 600
X = (100/15)*600
X = 100*40
X = 4,000
Actual amount = #4,000
(2a)
(X^2 Y^3 Z)^3/4/X^1 Y^4 Z^5
= (X^2)^3/4/X^1 * (Y^3)^3/4/Y^4 * Z^3/4/Z^5
= X^3/2/X^1 * Y^9/4/Y^4 * Z^3/4/Z^5
=X^3/2+1 * Y^9/44 * Z^3/45
=X^5/2 * Y^25/4 * Z^17/4
=X^10/4 * Y^25/4 * Z^17/4
=(X^10/Y^25 Z^17)^1/4
(2b)
√2/k + √2 = 1/k  √2
Multiply both sides by (k+√2)(k√2)
√2(k√2) = k+√2
√2k√2 = k+√2
√2kk = 2+√2
K(√2 1) = 2+√2
K = 2+√2/√21
K = (2+√2)/1√2
Rationalizing
K = (2+√2) * 1+√2/1√2
K = (2+√2)(1+√2)/1  2
K = (2+√2)(1+√2)
K = 2+2√2 + √2+2
K = 4+3√2
(4)
Draw the diagram
(i) Arc length = Tita/360*2πr
= 72/360*2*22/7*14
=1/5*44*2
=88/5
=17.6cm
(ii) Perimeter of Sector = arc length +2r
=17.6+2(14)
=17.6+28
=45.6cm
(iii) Area of sector = Tita/360*πr²
=72/360*22/7*14/1*14/1
=1/5*22*2*14
=616/5
=123.2cm2
(5a)
Mode = mass with highest frequency = 35kg
Median is the 18th mass
= 40kg.
(5b)
In a tabular form
Under Masses(x kg)
30,35,40,45,50,55
Under frequency(f)
5,9,7,6,4,4
Ef = 35
Under XA
10, 5, 0, 5, 10, 15
Under F(XA)
50, 45, 0, 30, 40, 60
Ef(X  A) = 35
Mean = A + (Ef(X  A)/Ef)
= 40 + 35/35
= 40 + 1
= 41kg
(
x=a+by(eqi)
when y=5 and x=19
19=a+5b(eqii)
when y=10 and x=34
34=a+10b(eqiii)
solving eqii and eqiii
a+10b=34
a+5b=19
=>5b=15
b=15/5=3
putting b=3 in eqii
19=a+5(3)
19=a+15
a=1915
a=4
(8i)
Putting a=4 and b=3 in eqi
x=4+3y
This is the relationship between xand y
(8ii)
When y=7
x=4+3(7)
x=4+21
x=25
11a)
x+y/2 =11
x+y= 11*2
x+y= 22 (1)
xy= 4 (11)
x+y = 22(1)

xy= 4(11)
____________
2y = 18
y= 18/2
y=9
Substitute y=9 in equ 1
x+9=22
x=229
x=13
x=13, y=9
x+y= 13+9= 22
Sum of the two number
(11b)
(6x + 3) dx
(6x + 3)dx
(6x +3)^6  (6x + 3)^1
(6 x + 3)^5
(7776x^5 + 243)
38,880x/6 + 243
6480 x^6 + 243x
9(720x^6 + 27x)
(11c)
y = x² + 5x  3 (x = 2)
y = 2² + 5(2)  3
y = 4 + 10  3
y = 14  3
y = 11
Gradient of the curve = 11
Monday 4th June 2018
OBJ � General Mathematics � 10:00am � 11:45am
Essay � General Mathematics � 12:00noon �2:30pm
Mathematics Neco exam will be deliver Night Before the exam day, we are not going to post answers here for free, Check our previous exam>>> 2018 Neco Geography Objective & Practical / Physical Questions and Answers  Geography Expo
Also Read>> Neco 2018 Whatsapp Exam Runs Package  Neco Exam Expo
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2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
Also Read>> 2018 Neco Biology Objective and Essay Questions and Answers  Biology Expo
2018 Neco Mathematics Objective and Theory Questions and Answers is available ,all you need to do is to follow the instructions above, get verified Mathematics Objective and Theory Questions and Answers here, question and answers are now Available. expo for Neco 2018 Mathematics, exam runs for Mathematcs objective and Theory questions and answers
Last edited by Emmi on Mon Jun 04, 2018 11:58 am; edited 6 times in total