*===============================================================*

*MATHS-OBJ*

1-10: DBBCBDEDAC

11-20: DCDAECDEDC

31-40: CCACCBDDCC

41-50: CDDDCABDBA

*===============================================================*

*KEEP REFRESHING THIS VIP*

*===============================================================*

(2a)

3^2x-y=1

3^2x-y=3^0

2x-y=0-------------(1)

16^x/4 = 8^3x-y

2^4x/2^2 = 2^3(3x-y)

2^4x-2 = 2^9x-3y

:. 4x-2 = 9x-3y

4x-9x+3y= 2

-5x+3y=2------------(2)

From equation (1):

2x-y=0

y=2x--------(3)

Substitute for y in equation (2)

-5x+3y=2

-5x+3(2x)=2

-5x+6x=2

x=2

Substitute for x in equation (3)

y=2x

y=2(2)=4

:.x=2, y=4

(2b)

x² - 4/3 + x+3/2

2(x² - 4) + 3(x +3)/ 6

2x² - 8 + 3x + 9/6

2x²+3x+1/6

(2x² + 2x)+(x+1)/6

2x(x+1) +1 (x+1)/6.

*===============================================================*

(3)

Using SOHCAHTOA

|TM| / |MD| = Tan28°

298.5+1.5/|MD| = 0.5317

|MD| = 300/0.5317 = 564.2m

Similarly,

|TM| / |MC| = Tan34°

300/ |MC| = 0.6745

|MC| = 300/0.6745 = 444.8m

Distance between both , ΔCD

= 564.2 - 444.8

= 119.4m

SEE THE IMAGE(3)

(4)

Mark: 1-5, 6-10, 11-15, 16-20, 21-25, 26-30

F: 6,4,5,5,6,4

x: 3,8,13,18,23,28

Fx: 18,32,65,90,138,112

x-x: -12.167, -7.167, -2.167, 2.833, 7.833, 12.833

(x-x)^2: 148.0359, 51.3659, 4.6959, 8.0259, 61.3559, 164.6859

f(x-x)^2: 888.2154, 205.4636, 23.4795, 40.1295, 368.1354, 658.7436

Mean(x) = Σfx/Σf = 455/30 =15.167

Variance = Σf(x-x)^2/Σf = 2184.167/30 = 72.8056

= 72.81(approximation.)

Standard deviation = √Variance

= √72.84

= 8.533

= 8.53 (approximation.)

SEE IMAGE(4)

*===============================================================*

(6a)

For X = a=4a , T6=256

ar^5=256

4ar^5/4=256/4

ar^5=64............(1)

For Y = a=3a, T5=48

ar^4=48

3ar^4/3=48/3

ar^4=16...............(2)

Divide equ (2) by (1):

ar^5/ar^4=64/16

r=4

Substitute for r in equ (2)

ar^4=16

a × 4^4=16

256a/256=16/256

a=1/16

(6ai)

First term of x : a=4a

a=4×1/16=1/4

(6aii)

Sn = a(r^n-1)/r-1

S4 = 1/4(4^4 -1)/4-1

=1/4(256-1)/3

=1/4 × 255/3

=85/4

S4=21.25

(6b)

y(4x+2)^-3

Let u =4x+2, y=u^-3

du/dx=4, dy/du= -3u^-4

dy/dx=dy/du * du/dx

= -3u^-4 × 4

= -12u^-4

dy/dx= -12(4x+2)^-4

When x =1,

dy/dx= -12(4*1+2)^-4

= -12(4+2)

= -12 * 6^-4

= -12/6^4

= -12/1296

= -1/108

*===============================================================*

(7a)

4x^2 - 9y^2 = 19

2x^2 x^2 - 3^2 y^2=19

(2x-3y)(2x+3y)=19

Substitute for 2x+3y=1

2x-3y=19............(1)

2x+3y=1..............(2)

Subtract equ (2) from (1)

2x-3y-(2x+3y)=19-1

3x-3y-2x-3y=18

-6y/-6=18/-6

y = -3

Substitute for y in equ (1)

2x-3(-3)=19

2x+9=19

2x/2=10/2

x=5

(7b)

Typing

SEE IMAGE(7)

*===============================================================*

(8ai)

Total surface area

= Total surface of cylinder + Curve surface of hemisphere

= (πr^2+2πrh) + (2πr^2)

= π(r^2 + 2rh) + π(2r^2)

= π[(r^2 + 2rh) + 2r^2]

= π[(7^2 + 2(7)(10) + 2(7)^2]

= π[(49+140) + 98]

= π(287)

= 287πcm^2

Using π=22/7

Total surface area =287×22/7 = 41×22

= 902cm^2

(8aii)

Volume = Volume of cylinder + volume of hemisphere

= πr2h + 2/3πr^3

= π[r^2h + 2/3r^3]

= π[(7^2)(10) + 2/3(7)^3]

= π(490 + 656/3)

= π(2156/3)

= 22/7 × 2156/3

= 22 × 308/3 = 6776/3

= 2258.67cm^3

(8b)

Perimeter of Arc = Φ/360 × 2πr

= 120/360 × 2 × 22/7 × 7

= 1/3 × 44 = 44/3

= 14.67cm

SEE IMAGE( *===============================================================*

(10ai)

S=t^3 -3t -9t + 1

ds/dt=v

:. 3t^2 - 6t^2 -9

When v=0

3t^2 -6t^2 -9=0

(3t^2 -9t)+(3t-9)

3t(t-3)+3(t-3)=0

(3t+3)(t-3)=0

3t + 3=0

3t= -3

t= -3/3= -1 or t -3=0

t=3seconds

(10aii)

a=dv/dt = 3t^2 -6t -9= 6t -6

a=6t -6

When a=0

6t -6=0

6t=0+6

6t=6

t=6/6

t=1

(10b)

v=3t^2 -6t -9

When t=2seconds

v=3(2)^2 -6(2) -9

= 3*4-9-12-9= -9m/s

v= -9m/s

acceleration, a when t=2seconds

a=6t -6= 6(2) -6= 12-6

a=6m/s^2

(10c)

a=6t -6 = 36-6=30

a=30m/s^2

SEE IMAGE(10)

*===============================================================*

2019 NECO Mathematics Objective and theory Questions and Answers is available at 9Jatechs, get verified Mathematics Objective and theory neco questions and answers  midnight before the commencement of the examination.

OUR SUBSCRIBERS GET QUESTIONS AND ANSWERS MIDNIGHT BEFORE THE COMMENCEMENT OF THE EXAM.

Time and Date for Mathematics Objective and theory  2019 NECO Examination.

Monday 24th June

• Paper III: Objective – General Mathematics ‹‹›› 10:00am – 11:45am

• Paper II: Essay – General Mathematics ‹‹›› 12:00noon – 2:30pm

Recommended: See 2019 NECO Official Exam Timetable >> 9Jatechs

2019 Neco
Mathematics Objective and theory Answers will be deliver to  all 9Jatechs Subscribers at night before the exam day,  you can also get free exam Expo on our portal(i. e  we are going to post answers 1hour after the exam start)  just like we did during  the previous Physics Practical 2018 NECO Examination

Procedure on How To Subscribe for 2019/2020 NECO
Mathematics Objective and theory  Questions and Answers.

We only Run our exam runz on whatsapp (2019 Neco WhatsApp Exam runz Package ) because it is the fastest  means of sending messages and photos online.
Mathematics Objective and theory Questions and Answers Cost N800 MTN recharge card.

Procedure on how to Subscribe On Whatsapp

To subscribe forMathematics Objective and theory Questions and Answers on WhatsApp you can send your MTN pin via WhatsApp or SMS.
(e.g. MTN Recharge Pin, Subject , Whatsapp Number to 08065889844)

Note:9Jatechs 2019 NECO
Mathematics Objective and theory Questions and Answers is N800 MTN Card

Note: please do not call our number, simply send message on whatsapp or using SMS
For More Info Whatsapp 08065889844 or click the whatsapp icon on the left side of our platform to chat with us.

2019/2020
Neco
Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

2019/2020 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

2019/2020 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

ALSO SEE: Physics Objective and Essay 2018 Neco Gce Questions and Answers

2019/2020 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

2019/2020 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

2019/2020 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for 2019 Neco Mathematics Objective and theory Questions and answers now available, To get all questions and answers for Mathematics Objective and theory.

9Jatechs deliver it answers at midnight  to her subscribe. Expo for 2019 Neco
Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs). 9Jatechs deliver it answers at midnight  to her subscribe.  Expo for 2019 Neco Mathematics Objective and theory Questions and answers is also available on our portal (9Jatechs).

All updates concerning Neco is been posted at Neco exam  forum and all updates concerning Waec is posted at Waec Exams forum  forum.